Sip Posted February 9, 2006 Report Share Posted February 9, 2006 Assuming the table is all clear, Azat, sounds to me like you would want to go first. Put your bottle at the center of the table ... then where ever your oponent puts a bottle, just put yours at the opposide side of the center in the exact same spot (in the next turn). This way, your oponent is guaranteed to run out of space before you do. Quote Link to comment Share on other sites More sharing options...
Sip Posted February 9, 2006 Report Share Posted February 9, 2006 Hahahahah ... Vava, how did you guess what I was typing? Quote Link to comment Share on other sites More sharing options...
vava Posted February 9, 2006 Report Share Posted February 9, 2006 That's awesome!! Quote Link to comment Share on other sites More sharing options...
Azat Posted February 9, 2006 Report Share Posted February 9, 2006 I am not sure if this would work. Movses, Sip Vava and I need about 200 bottles of nice wine and a bistro table to try this. good job guys. Quote Link to comment Share on other sites More sharing options...
Sip Posted February 9, 2006 Report Share Posted February 9, 2006 (edited) I hear ketchup bottles work just as well But now I see your ulterior motives for posing the question!!! Here's another one ... I thought it was pretty cool: So, there are n Armenians in Glendale, each having a unique piece of gossip. They all want to know everything. Their only mode of communication is the phone. When two people make a call to each other, ALL their gossip knowledge gets exchanged ... so they will both know all that each other knew before calling. Given that these are highly efficient Armenians, what is the minimum number of calls required for ALL of them to learn ALL the gossip? They can only do a normal one-on-one call. There is no conference calling or text messaging or anything like that. Edited February 9, 2006 by Sip Quote Link to comment Share on other sites More sharing options...
gevo Posted February 9, 2006 Report Share Posted February 9, 2006 So, this is not one person sharin with n people, its all the n persons sharing everyting they know? Quote Link to comment Share on other sites More sharing options...
MosJan Posted February 9, 2006 Report Share Posted February 9, 2006 I am not sure if this would work. Movses, Sip Vava and I need about 200 bottles of nice wine and a bistro table to try this. good job guys. ok yerb ?? Quote Link to comment Share on other sites More sharing options...
DominO123 Posted February 10, 2006 Report Share Posted February 10, 2006 I hear ketchup bottles work just as well But now I see your ulterior motives for posing the question!!! Here's another one ... I thought it was pretty cool: So, there are n Armenians in Glendale, each having a unique piece of gossip. They all want to know everything. Their only mode of communication is the phone. When two people make a call to each other, ALL their gossip knowledge gets exchanged ... so they will both know all that each other knew before calling. Given that these are highly efficient Armenians, what is the minimum number of calls required for ALL of them to learn ALL the gossip? They can only do a normal one-on-one call. There is no conference calling or text messaging or anything like that. I'm too old for this sort of things now. I'll quickly say n-1, but I know that this answer is wrong, too simplistic... and fried the brain cells that will make me think about such things without a headache. I have emailed the answer to Azat, Vava and Harut so that they can take the credit for. Quote Link to comment Share on other sites More sharing options...
Sip Posted February 10, 2006 Report Share Posted February 10, 2006 Try n=2, 3, and 4. Once you try those, then we'll go from there. I'll give you a hint that it may be different from small n. But for large n, there is a formula. Quote Link to comment Share on other sites More sharing options...
vava Posted February 10, 2006 Report Share Posted February 10, 2006 It's definitely not n-1 That would leave too many people without ALL the gossip. Besides for the simple case of 4 glendale armenians, it would have to be a minimum of 4 calls. Taking armenians A,B,C & D: A <--> B C <--> D then A <--> C & B <-->D and voila - they all know. I think 4 is a critical number here, cause above 4 you will need a greater number of calls than the "n" number of Armenians. This is the type of discrete mathematics that keep comp-sci geeks busy (and happy), right sip? Without attempting a classical mathematics proof, i've tried to determine the formula through a series: when n=x, (y)=calls are required: 1, (0) 2, (1) 3, (3) 4, (4) as shown above 5, (6) 6, (8) 7, (10) 8, (12) 9, (14) 10, (16) OK, this is getting long. But I see a pattern - and it seems that the original 4 is a constant. I would say that the solution would be something like 2n-4; but it only works for values above 4. So it's probably not right - alas I have no proof, and i never liked discrete math. Go ahead sip - give us the solution! Quote Link to comment Share on other sites More sharing options...
Sip Posted February 10, 2006 Report Share Posted February 10, 2006 (edited) I'll give a recursive solution: refer to the previous post. Edited February 10, 2006 by Sip Quote Link to comment Share on other sites More sharing options...
Azat Posted February 10, 2006 Report Share Posted February 10, 2006 2*n*n-1/n Quote Link to comment Share on other sites More sharing options...
DominO123 Posted February 10, 2006 Report Share Posted February 10, 2006 It's definitely not n-1 I know, I didn't pay attention to the word ALL Quote Link to comment Share on other sites More sharing options...
Azat Posted September 19, 2006 Report Share Posted September 19, 2006 Another one from cartalk. Please dont search the web for the answer. thats cheating... I'm going to give you four numbers: 2,3,4, and 5. And they're not Roman numerals, they're the regular old Arabic numerals with which we're all familiar. You also get a plus sign, and an equal sign. Now, make an equation with some stuff on one side of the equal sign, and some stuff on the other. At first blush, you might say, "This is easy!" 5+2=3+4...but, you're using two plus signs, and you're only allowed to use one. Quote Link to comment Share on other sites More sharing options...
Sip Posted September 19, 2006 Report Share Posted September 19, 2006 You've got PM Quote Link to comment Share on other sites More sharing options...
Harut Posted September 19, 2006 Author Report Share Posted September 19, 2006 eh? maybe 5+3=2 4? that is, 2x4... or something similar... Quote Link to comment Share on other sites More sharing options...
Azat Posted September 19, 2006 Report Share Posted September 19, 2006 I got PMS. think more Harut jan Quote Link to comment Share on other sites More sharing options...
ExtraHye Posted September 19, 2006 Report Share Posted September 19, 2006 I got PMS. Quote Link to comment Share on other sites More sharing options...
Azat Posted September 19, 2006 Report Share Posted September 19, 2006 What? I got multiple Personal Messages from Sip. PMS Quote Link to comment Share on other sites More sharing options...
Yervant1 Posted September 19, 2006 Report Share Posted September 19, 2006 4/2+3=5 Quote Link to comment Share on other sites More sharing options...
Yervant1 Posted September 19, 2006 Report Share Posted September 19, 2006 What? I got multiple Personal Messages from Sip. PMS Wrong my friend!!!! That is MPM Quote Link to comment Share on other sites More sharing options...
Harut Posted September 19, 2006 Author Report Share Posted September 19, 2006 4/2+3=5 you used a division sign... Azat, could we do that? Quote Link to comment Share on other sites More sharing options...
Azat Posted September 20, 2006 Report Share Posted September 20, 2006 you used a division sign... Azat, could we do that? nops. you are right Mr Bear. I do have MPMS Quote Link to comment Share on other sites More sharing options...
Eva Posted September 20, 2006 Report Share Posted September 20, 2006 I have a question,can we use power signs like 2^2 ? Quote Link to comment Share on other sites More sharing options...
Eva Posted September 20, 2006 Report Share Posted September 20, 2006 or can we say " to the second power"? Quote Link to comment Share on other sites More sharing options...
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.