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Harut

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quote:
Originally posted by nairi:

Okay, let me try one more ...


Yup, I'd say you now know binary ... welcome to the world of 1's and 0's ... as you see, there is nothing complicated about it!

 

Everything, and I do mean EVERYTHING in your computer is done in binary. Amazing huh? You can do all this with just 1's and 0's.

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I saw this on someone's website and thought it was cool. I think I have an answer for it. Here is the problem:

 

code:
 ___________

|_____|_____|

|__|_____|__|


Your task is to draw a single line (i.e. without "lifting the pencil" that crosses all those lines in that picture ONLY ONCE. You can start and end where ever you want but you can only cross each line once. Note that those are supposed to be rectangles in that diagram above

 

---

EDIT: Forgot to post a link to the site! He has a nice animation to get you started HERE.

 

[ August 30, 2002, 04:04 AM: Message edited by: Sip ]

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  • 3 weeks later...

1) 50==>  20<--->20        10

 

2) 20==>   8<--->8           4

    10==>   4<--->4           2

 

3)  8==>    3<--->3           2

     4==>    1<--->1           2

 

4)   2==>   1<--->1           0

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code:
                            9

 

 

 

 

 

_________________________________________

| | |

| 4 1 | 2 8 |

| | |

10 _________________________________________ 12

| | | |

| | 3 | |

| | 5 7 | |

_________________________________________

 

 

6

 

 

 

 

 

11


Join the dots: 1, 2, 3, 1, 4, 5, 6, 7, 8, 9, 10, 11, 12, 8, so you get three triangles.
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http://zr2.cs.ucla.edu/hf/nairi_sol.gif

Nairi jan, nice try but either the 5-6 or the 6-7 doesn't work They cross the same line (twice).

 

By the way, AMD.PL ... nice setup! You got me curious. Is there a question there somewhere? I couldn't figure out!

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Darn, I was hoping you hadn't seen that yet. Was going to edit it now with this:

 

code:
                            3

 

 

 

 

 

_________________________________________

| | |

| 7 | 8 |

| | |

2 _________________________________________ 4

| | | |

| 6 | 5 | 9 |

| | | |

_________________________________________

 

 

 

 

 

 

 

 

1


Join the dots: 1, 2, 3, 4, 1, 5, 6, 7, 8, 9, 5.
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Yes, the line under 7 and 8 (there are actually 2 lines) ... basically, one from 7-5 and one from 5-8. The original solution you had was almost perfect, except for the red part which I highlighted.

 

[ September 20, 2002, 02:25 PM: Message edited by: Sip ]

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quote:
Originally posted by Sip:

Does it mean that you are retarded?


You be the judge:

 

code:
                      2

 

 

 

 

 

 

_________________________________________

| 5/8 |

| | |

1 | | |

| | |

_________________________________________

| | | |

| | | |

| | 11 | | 3

| | | |

6 _________________________________________

 

4

7 10 9

 

 

 

 

Join the dots.


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quote:
Originally posted by nairi:

quote:
Originally posted by Sip:

Does it mean that you are retarded?


You be the judge
I think I am very confident that that is not true. Consequently, I am certain that "the second case" (from my previous post) must be true. It fact I can prove it

 

Regarding the latest solution, 4-5-6 and then 7-8 must both pass through the line that is right below the 5/8

 

[ September 21, 2002, 07:50 PM: Message edited by: Sip ]

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Sip jan. this was not a good question my friend. Because I spent 2 hour at work one day trying to figure it out(well, what else should I do at work? ) But now that you have said that you have said that it is impossible to do i think I can prove it as well. and I don't need to go to work and spent another 2 hours to prove this answer to you.(that is if I had work to go to ) everyone crosses one line twice and there is a reason why and I can prove that it will always be like that.

 

Never the less shame on you for making all of us run in circles. To get back to you one day I am going to make you solve pi or maybe drive behind Movses.

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hi hi hi

 

That reminded me of the BEST excuse I have ever heard for not doing homework ... a friend of mine actually told this to our teacher, senior year in highschool! The teacher asked him why he didn't turn in his homework ... he calmly and without hesitation replied: Well, I was doing it last night but I accidentally divided by zero and got stuck.

 

... the teacher got very amused by that so gave him an extra day. I was totally http://zr2.cs.ucla.edu/Sip/zr2/roflmao.gif

 

By the way, "I did it for 2 hours and it didn't work" is not a good enough proof (I am saying this for Harut) ... He has been VERY quiet in here lately. Harut, can you come up with the proof?

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quote:
Originally posted by Sip:

Regarding the latest solution, 4-5-6 and then 7-8 must both pass through the line that is right below the 5/8
It works though! Join 7 with 8 and 8 with 9 and you'll cross both those lines. I know the diagram is not the best representation, but it works. The only thing that doesn't work is that I cross 5 twice.

 

quote:
It fact I can prove it
I'm anticipating.
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quote:
Originally posted by Sip:

You have 9. You add 5 and get 2 as the answer. How did it happen?


it all started back in old days when your mom dropped you on your head.

 

sorry, i'm just in "stupid" mood today.

this is what happens when minors start drinking.

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quote:
Originally posted by Sip:

Harut, can you come up with the proof?


two upper rectangles and lower middle rectangle theoretically have 5 sides.

so, if you start(from outside of the rectangle) crossing each line you will end up inside the rectagle. if you start(from inside of the rectangle) crossing each line you will end up outside of the rectangle.

so, because we have three 5-sided rectangles, we cannot do it.

we can start from inside of one 5-side rectangle, but when we enter inside the second one, there is no way out!

 

i hope this makes sense.

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